The negation of p wedge (q rightarrow r) is | vedclass

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(B) To find the negation of $p \wedge (q \rightarrow r)$,we apply De Morgan's Law and the properties of implication: $\sim [p \wedge (q \rightarrow r)

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$\sim p \vee (q \wedge \sim r)$

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(B) To find the negation of $p \wedge (q \rightarrow r)$,we apply De Morgan's Law and the properties of implication: $\sim [p \wedge (q \rightarrow r)]$ Since $q \rightarrow r \equiv \sim q \vee r$,we have: $\equiv \sim [p \wedge (\sim q \vee r)]$ Applying De Morgan's Law $\sim (A \wedge B) \equiv \sim A \vee \sim B$: $\equiv \sim p \vee \sim (\sim q \vee r)$ Applying De Morgan's Law again $\sim (A \vee B) \equiv \sim A \wedge \sim B$: $\equiv \sim p \vee (q \wedge \sim r)$

The negation of $p \wedge (q \rightarrow r)$ is

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