The number of lines of force originating from | vedclass

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Question

(B) According to Gauss's Law, the total number of electric field lines $N$ originating from a charge $q$ placed in a medium with dielectric constant $

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(B) According to Gauss's Law, the total number of electric field lines $N$ originating from a charge $q$ placed in a medium with dielectric constant $\epsilon_r$ is given by the formula $N = q / (\epsilon_0 \epsilon_r)$.Given:Charge $q = 2 	imes 8.85 	imes 10^{-9} 	ext{ C}$Dielectric constant $\epsilon_r = 10$Permittivity of free space $\epsilon_0 = 8.85 	imes 10^{-12} 	ext{ SI unit}$Substituting the values into the formula:$N = (2 	imes 8.85 	imes 10^{-9}) / (8.85 	imes 10^{-12} 	imes 10)$$N = (2 	imes 8.85 	imes 10^{-9}) / (8.85 	imes 10^{-11})$$N = 2 	imes 10^{-9} / 10^{-11}$$N = 2 	imes 10^2 = 200$.Therefore, the number of lines of force is $200$.

The number of lines of force originating from a point charge of $2 \times 8.85 \times 10^{-9} \text{ C}$ in a medium of dielectric constant $10$ is $(\epsilon_0 = 8.85 \times 10^{-12} \text{ SI unit})$.

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