The number of octahedral and tetrahedral hole | vedclass

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Question

(A) In a close packed structure ($hcp$ or $ccp$): $(i)$ The number of octahedral voids is equal to the number of particles $(N)$ present in the close

Vedclass · Accepted Answer

$X, 2X$

Vedclass · Answer

(A) In a close packed structure ($hcp$ or $ccp$): $(i)$ The number of octahedral voids is equal to the number of particles $(N)$ present in the close packing. (ii) The number of tetrahedral voids is equal to $2 	imes N$,where $N$ is the number of particles. Given that there are '$X$' atoms,the number of octahedral voids is '$X$' and the number of tetrahedral voids is '$2X$'. Therefore,the correct option is $A$.

The number of octahedral and tetrahedral holes respectively present in a hexagonal close packed $(hcp)$ crystal of '$X$' atoms are

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