The parametric equations of the circle 2x^2 + | vedclass

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(C) The given equation of the circle is $2x^2 + 2y^2 = 9$. Dividing by $2$,we get $x^2 + y^2 = \frac{9}{2}$. This is in the form $x^2 + y^2 = r^2$,whe

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$x = \frac{3}{\sqrt{2}} \cos 	heta, y = \frac{3}{\sqrt{2}} \sin 	heta$

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(C) The given equation of the circle is $2x^2 + 2y^2 = 9$. Dividing by $2$,we get $x^2 + y^2 = \frac{9}{2}$. This is in the form $x^2 + y^2 = r^2$,where $r^2 = \frac{9}{2}$,so $r = \frac{3}{\sqrt{2}}$. The parametric equations for a circle $x^2 + y^2 = r^2$ are given by $x = r \cos 	heta$ and $y = r \sin 	heta$. Substituting $r = \frac{3}{\sqrt{2}}$,we get $x = \frac{3}{\sqrt{2}} \cos 	heta$ and $y = \frac{3}{\sqrt{2}} \sin 	heta$.

The parametric equations of the circle $2x^2 + 2y^2 = 9$ are

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