The phase difference between the input voltage and the output voltage in a common emitter amplifier is (in $^{\circ}$)

In the circuit shown,the transistor used has a current gain $\beta = 100$. What should be the base resistor $R_B$ so that $V_{CE} = 5\,V$ and $V_{BE} = 0\,V$?

The current gain of a transistor is $0.98$. If the transistor is used in a common emitter arrangement, what would be the change in collector current corresponding to a change of $0.5 \,mA$ in the base current (in $\,mA$)?

To use a transistor as an amplifier,

In a common base mode of a transistor,the collector current is $5.488 \ mA$ for an emitter current of $5.60 \ mA$. The value of the base current amplification factor $(\beta)$ will be

In a common emitter configuration,an $N-P-N$ transistor is connected. The current gain of the transistor is $100$. If the collector current changes by $1 \ mA$,by how much will the emitter current change in $mA$?