The plates of a parallel plate capacitor are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the initial distance between the plates be $d$. The initial potential difference is $V = E_0 d$,where $E_0$ is the electric field between the

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) Let the initial distance between the plates be $d$. The initial potential difference is $V = E_0 d$,where $E_0$ is the electric field between the plates.When a dielectric slab of thickness $t = 2\, mm$ is inserted,the new distance between the plates becomes $d' = d + 1.6\, mm$.The potential difference $V$ remains the same. The electric field in the dielectric is $E = E_0 / K$.The new potential difference is $V = E_0(d' - t) + E t = E_0(d + 1.6 - 2) + \frac{E_0}{K}(2)$.Since $V = E_0 d$,we have $E_0 d = E_0(d - 0.4) + \frac{2 E_0}{K}$.Dividing by $E_0$,we get $d = d - 0.4 + \frac{2}{K}$.$0.4 = \frac{2}{K}$.$K = \frac{2}{0.4} = 5$.

The plates of a parallel plate capacitor are charged up to $100\, V$. $A$ $2\, mm$ thick plate is inserted between the plates. To maintain the same potential difference,the distance between the capacitor plates is increased by $1.6\, mm$. The dielectric constant of the plate is:

Similar Questions

The sensitivity of a galvanometer is $60 \text{ division/A}$. When a shunt is used,its sensitivity becomes $10 \text{ division/A}$. If the galvanometer is of resistance $20 \ \Omega$,the value of shunt used is: (in $\Omega$)

$A$ particle is projected vertically upwards from a point $A$ on the ground. It takes time $t_1$ to reach a point $B$,and it continues to move up. If it takes a further time $t_2$ to reach the ground from point $B$,then the height of point $B$ from the ground is:

Two nuclei have their mass numbers in the ratio of $1:3$. The ratio of their densities would be

$A$ particle falls from a height $h$ upon a fixed horizontal plane and rebounds. If $e$ is the coefficient of restitution,the total distance travelled before rebounding has stopped is

$A$ and $B$ are two metallic rings placed at opposite sides of an infinitely long straight conducting wire as shown. If the current in the wire is slowly decreased,the direction of the induced current will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module