The points (3a, 0),(0, 3b),and (a, 2b) are: | vedclass

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(D) Let the points be $A(3a, 0)$,$B(0, 3b)$,and $C(a, 2b)$.To check if the points are collinear,we calculate the area of the triangle formed by these

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Collinear

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(D) Let the points be $A(3a, 0)$,$B(0, 3b)$,and $C(a, 2b)$.To check if the points are collinear,we calculate the area of the triangle formed by these points:$	ext{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$$	ext{Area} = \frac{1}{2} |3a(3b - 2b) + 0(2b - 0) + a(0 - 3b)|$$	ext{Area} = \frac{1}{2} |3a(b) + 0 - 3ab|$$	ext{Area} = \frac{1}{2} |3ab - 3ab| = 0$Since the area of the triangle is $0$,the points are collinear.

The points $(3a, 0)$,$(0, 3b)$,and $(a, 2b)$ are:

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