The points A(a, 0),B(0, b),C(c, 0),and D(0, d | vedclass

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(D) Let the origin be $O(0, 0)$. The points $A, B, C, D$ lie on the coordinate axes.According to the power of a point theorem,if two chords $AC$ and $

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are concyclic

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(D) Let the origin be $O(0, 0)$. The points $A, B, C, D$ lie on the coordinate axes.According to the power of a point theorem,if two chords $AC$ and $BD$ of a circle intersect at a point $O$,then $OA 	imes OC = OB 	imes OD$.Here,the coordinates are $A(a, 0)$,$C(c, 0)$,$B(0, b)$,and $D(0, d)$.The distances from the origin are $OA = |a|$,$OC = |c|$,$OB = |b|$,and $OD = |d|$.The condition given is $ac = bd$. If we consider the signed distances or the product of the coordinates,the condition $OA 	imes OC = OB 	imes OD$ is satisfied.Therefore,the points $A, B, C, D$ are concyclic.

The points $A(a, 0)$,$B(0, b)$,$C(c, 0)$,and $D(0, d)$ are such that $ac = bd$ and $a, b, c, d$ are all non-zero. Then the points:

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