The principal solutions of cot x = sqrt{3} ar | vedclass

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(B) The given equation is $\cot x = \sqrt{3}$,which is equivalent to $	an x = \frac{1}{\sqrt{3}}$.We know that $	an \frac{\pi}{6} = \frac{1}{\sqrt{3

Vedclass · Accepted Answer

$\frac{\pi}{6}, \frac{7 \pi}{6}$

Vedclass · Answer

(B) The given equation is $\cot x = \sqrt{3}$,which is equivalent to $	an x = \frac{1}{\sqrt{3}}$.We know that $	an \frac{\pi}{6} = \frac{1}{\sqrt{3}}$.Since $	an x$ is positive in the first and third quadrants,the principal solutions lie in the interval $[0, 2\pi)$.The first solution is $x = \frac{\pi}{6}$.The second solution in the third quadrant is $x = \pi + \frac{\pi}{6} = \frac{7\pi}{6}$.Thus,the principal solutions are $\frac{\pi}{6}$ and $\frac{7\pi}{6}$.

The principal solutions of $\cot x = \sqrt{3}$ are

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