The product formed when hydroxylamine $(NH_2OH)$ condenses with a carbonyl compound is called:

Which of the following does not give alcohol with $NaBH_4$?

Match List-$I$ with List-$II$.
List-$I$ (Reaction):
$A$. Bicyclohexylidene $\rightarrow$ $2$ Cyclohexanone
$B$. Benzene $\rightarrow$ Benzophenone
$C$. Cyclohexanol $\rightarrow$ Cyclohexanone
$D$. Ethylbenzene $\rightarrow$ Potassium benzoate
List-$II$ (Reagents/Condition):
$I$. Benzoyl chloride / Anhydrous $AlCl_3$
$II$. $CrO_3$
$III$. $KMnO_4 / KOH, \Delta$
$IV$. $(i) O_3, (ii) Zn-H_2O$
Choose the correct answer from the options given below:

Given below are the four isomeric compounds $(P, Q, R, S)$. Identify the correct statements from below.
$A$. $Q, R$ and $S$ will give a precipitate with $2,4-DNP$.
$B$. $P$ and $Q$ will give a positive Bayer's test.
$C$. $Q$ and $R$ will give a sooty flame.
$D$. $R$ and $S$ will give a yellow precipitate with $I_2/NaOH$.
$E$. $Q$ alone will deposit silver with Tollen's reagent.
Choose the correct option.

Identify $A$ and $B$ from the following reactions:
$(I)$ $CH_3-CH=CH-CH_3 \xrightarrow{\text{(i) } O_3}{\text{(ii) } Zn-H_2O} 2X$
$(II)$ $2X$ $\xrightarrow[2. \Delta]{1. NaOH \text{ (dil.)}} Z$ $\xrightarrow[\text{(ii) } Zn-H_2O]{\text{(i) } O_3} A + B$

The product $(A)$ in the following reaction is: