The quadratic equation having roots -1 and 2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) quadratic equation with roots $\alpha$ and $\beta$ is given by the formula: $(x - \alpha)(x - \beta) = 0$.
Given the roots are $\alpha = -1$ and

Vedclass · Accepted Answer

$x^{2}-x-2=0$

Vedclass · Answer

(D) quadratic equation with roots $\alpha$ and $\beta$ is given by the formula: $(x - \alpha)(x - \beta) = 0$.
Given the roots are $\alpha = -1$ and $\beta = 2$.
Substituting these values into the formula,we get: $(x - (-1))(x - 2) = 0$.
This simplifies to: $(x + 1)(x - 2) = 0$.
Expanding the expression: $x(x) + x(-2) + 1(x) + 1(-2) = 0$.
$x^{2} - 2x + x - 2 = 0$.
$x^{2} - x - 2 = 0$.
Therefore,the correct quadratic equation is $x^{2} - x - 2 = 0$.

The quadratic equation having roots $-1$ and $2$ is .... .

Similar Questions

Verify whether the given value of $x = \frac{-2}{m+n}$ is a solution of the quadratic equation $(m+n)^{2} x^{2} + (m+n) x - 2 = 0$ or not.

Represent the following situation in the form of a quadratic equation:
The area of a rectangular plot is $528 \ m^{2}$. The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.

Solve the equation $x^{2}-8x-21=0$ using the quadratic formula.

Which constant should be added and subtracted to solve the quadratic equation $4x^{2} - \sqrt{3}x - 5 = 0$ by the method of completing the square?

Find the roots of the following quadratic equation by the method of completing the square: $x^{2}-4 \sqrt{2} x+6=0$

Vedclass Test Series

Exam Paper Generator

Online Exam Module