The reaction of chloroform with alcoholic KOH | vedclass

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Question

(A) The reaction of a primary amine with chloroform $(CHCl_3)$ and alcoholic $KOH$ is known as the carbylamine reaction.$p-$toluidine $(CH_3-C_6H_4-NH

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$p-$tolyl isocyanide

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(A) The reaction of a primary amine with chloroform $(CHCl_3)$ and alcoholic $KOH$ is known as the carbylamine reaction.$p-$toluidine $(CH_3-C_6H_4-NH_2)$ is a primary aromatic amine.When it reacts with $CHCl_3$ and alcoholic $KOH$,it undergoes the carbylamine reaction to form an isocyanide (carbylamine) as the product.The chemical reaction is:$CH_3-C_6H_4-NH_2 + CHCl_3 + 3KOH(alc.) \rightarrow CH_3-C_6H_4-NC + 3KCl + 3H_2O$Thus,the product formed is $p-$tolyl isocyanide.

The reaction of chloroform with alcoholic $KOH$ and $p-$toluidine forms:

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