The readings of the voltmeter and ammeter in the circuit shown in the diagram are respectively

$A$ new flashlight cell of $e.m.f.$ $1.5\, V$ gives a current of $15\, A$,when connected directly to an ammeter of resistance $0.04\,\Omega$. The internal resistance of the cell is ........... $\Omega$.

The current from the battery in the circuit diagram shown is .............. $A$.

In terms of resistance $R$ and time $T$,the dimensions of the ratio $\frac{\mu}{\varepsilon}$ of the permeability $\mu$ and permittivity $\varepsilon$ is:

The storage battery of a car has an emf of $12 \ V$. If the internal resistance of the battery is $0.6 \ \Omega$,then the maximum current that can be drawn from the battery is . . . . . . . (in $A$)

The series combination of two batteries,both of the same emf $10 \; V,$ but different internal resistances of $20 \; \Omega$ and $5 \; \Omega,$ is connected to the parallel combination of two resistors $30 \; \Omega$ and $R \; \Omega.$ If the voltage difference across the battery of internal resistance $20 \; \Omega$ is zero,the value of $R$ (in $\Omega$) is: