The reagent 'R' in the given sequence of chem | vedclass

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Question

(B) The given reaction sequence involves the conversion of $2,4,6$-tribromoaniline to $2,4,6$-tribromobenzenediazonium chloride using $NaNO_{2} / HCl$

Vedclass · Accepted Answer

$CH_{3}CH_{2}OH$

Vedclass · Answer

(B) The given reaction sequence involves the conversion of $2,4,6$-tribromoaniline to $2,4,6$-tribromobenzenediazonium chloride using $NaNO_{2} / HCl$ at $0-5^{\circ}C$. To replace the diazonium group $(-N_{2}^{+}Cl^{-})$ with a hydrogen atom,a reducing agent is required. Ethanol $(CH_{3}CH_{2}OH)$ acts as a mild reducing agent that reduces the diazonium salt to the corresponding aromatic hydrocarbon (in this case,$1,3,5$-tribromobenzene) while being oxidized to acetaldehyde. Therefore,the reagent '$R$' is $CH_{3}CH_{2}OH$.

The reagent '$R$' in the given sequence of chemical reaction is:

Similar Questions

The major product formed in the following reaction sequence is:

Which of the following is not correct regarding basic strength?

In the given reaction sequence:
$CH_3-CH_2-OH$ $\xrightarrow[(ii) H^{\oplus}]{(i) KMnO_4/OH^{\ominus}/\Delta} (A)$ $\xrightarrow[(ii) NH_3/\Delta]{(i) SOCl_2} (B)$ $\xrightarrow{Br_2/KOH} (C)$
$(C)$ will be:

Decarboxylation of all six possible isomers of diaminobenzoic acids $C_6H_3(NH_2)_2COOH$ yields three products $A, B$ and $C$. Three acids give product $A$,two acids give product $B$ and one acid gives product $C$. The melting point of product $C$ is .....$^{\circ} C$.

The correct order of basic strength for the given compounds is:

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