The resistance of a conductivity cell filled with $0.1 \ M$ $KCl$ solution is $100 \ \Omega$ and the conductivity is $1.70 \times 10^{-4} \ S \ cm^{-1}$. What is the cell constant of the cell (in $cm^{-1}$)?

The specific conductivity of $N/10$ $KCl$ solution at $20 \, ^oC$ is $0.012 \, \Omega^{-1} \, cm^{-1}$ and the resistance of the solution in the cell at $20 \, ^oC$ is $56 \, \Omega$. The cell constant is ........... $cm^{-1}$.

Calculate the molar conductivity of $0.2 \text{ M}$ $KCl$ solution at $298 \text{ K}$ if the conductivity $(k)$ is $0.0248 \text{ } \Omega^{-1} \text{cm}^{-1}$.

The equivalent conductances of two strong electrolytes at infinite dilution in $H_2O$ (where ions move freely through a solution) at $25 ^\circ C$ are given below:
$\Lambda _{CH_3COONa}^o = 91.0 \ S \ cm^2 / equiv.$
$\Lambda _{HCl}^o = 426.2 \ S \ cm^2 / equiv.$
What additional information/quantity one needs to calculate $\Lambda ^o$ of an aqueous solution of acetic acid?

Molar conductivities $\left(\Lambda_{m}^{\circ}\right)$ at infinite dilution of $NaCl$,$HCl$,and $CH_{3}COONa$ are $126.4$,$425.9$,and $91.0 \ S \ cm^{2} \ mol^{-1}$ respectively. $\Lambda_{m}^{\circ}$ for $CH_{3}COOH$ will be $:-$

The specific conductance $(\kappa)$ of $0.02 \ M$ aqueous acetic acid solution at $298 \ K$ is $1.65 \times 10^{-4} \ S \ cm^{-1}$. The degree of dissociation of acetic acid is [Given equivalent conductance at infinite dilution of $H^{+} = 349.1 \ S \ cm^{2} \ mol^{-1}$ and $CH_{3}COO^{-} = 40.9 \ S \ cm^{2} \ mol^{-1}$]