The sensitivity of a galvanometer that measures current is decreased by $\frac{1}{40}$ times by using a shunt resistance of $10 \Omega$. Then,the value of the resistance of the galvanometer is (in $\Omega$)

  • A
    $400$
  • B
    $410$
  • C
    $30$
  • D
    $390$

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Similar Questions

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