The solution of the differential equation $(x^2 + 1) \frac{dy}{dx} + (y^2 + 1) = 0$ is . . . . . .
- A$(A) \ x + y = c$
- B$(B) \ (x^2 + 1)(y^2 + 1) = c$
- C$(C) \ x^2 = y^2 + c$
- D$(D) \ \tan^{-1} x + \tan^{-1} y = c$
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