The solution of the differential equation $y dx - x dy + 3x^2 y^2 e^{x^3} dx = 0$ satisfying $y = 1$ when $x = 1$ is:

  • A
    $y(e^{x^3} - (1 + 2e)) - x = 0$
  • B
    $y(e^{x^3} + (1 - e)) + x = 0$
  • C
    $y(e^{x^3} + (1 + e)) - x = 0$
  • D
    $y(e^{x^3} - (1 + e)) + x = 0$

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