The species A,B,C,D formed in the following b | vedclass

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Question

(A) In the first reaction,$CH_3CH_2-I \rightarrow A + B$,the bond breaks heterolytically such that the bonding electron pair moves to the more electro

Vedclass · Accepted Answer

$CH_3CH_2^{+}, I^{-}, CH_3CH_2^{-}, Cu^{+}$

Vedclass · Answer

(A) In the first reaction,$CH_3CH_2-I \rightarrow A + B$,the bond breaks heterolytically such that the bonding electron pair moves to the more electronegative iodine atom. This results in the formation of an ethyl carbocation $(A = CH_3CH_2^{+})$ and an iodide ion $(B = I^{-})$.In the second reaction,$CH_3CH_2-Cu \rightarrow C + D$,the bond breaks heterolytically such that the bonding electron pair moves to the carbon atom because carbon is more electronegative than copper. This results in the formation of an ethyl carbanion $(C = CH_3CH_2^{-})$ and a copper cation $(D = Cu^{+})$.

The species $A$,$B$,$C$,$D$ formed in the following bond cleavages respectively are:

Similar Questions

The stability of the following carbanions is in the order of:

Which of the following carbocations lacks hyperconjugative stability?

The correct stability order of carbocations is

Which of the following are secondary radicals?
$(1) \ CH_3 - \dot{C}H - C_2H_5$
$(2) \ CH_2 = \dot{C} - CH_3$
$(3) \ CH_2 = CH - \dot{C}H_2$
$(4) \ (CH_3)_2 \dot{C}H$

Which of the following carbocations will not undergo rearrangement?

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