The standard Gibbs energy change for the Daniel cell reaction is $Zn_{(s)} + Cu^{2+}_{(aq)} \longrightarrow Zn^{2+}_{(aq)} + Cu_{(s)}$ where $E_{\text{cell}}^{\circ} = 1.1 \ V$.
- A$-212.3 \ kJ$
- B$106.15 \ kJ$
- C$+212.3 \ kJ$
- D$100 \ kJ$
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