The sum of the first n natural numbers is: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The sequence of the first $n$ natural numbers is $1, 2, 3, 4, \dots, n$,which forms an Arithmetic Progression $(A.P.)$ with the first term $a = 1$

Vedclass · Accepted Answer

$\frac{n(n + 1)}{2}$

Vedclass · Answer

(D) The sequence of the first $n$ natural numbers is $1, 2, 3, 4, \dots, n$,which forms an Arithmetic Progression $(A.P.)$ with the first term $a = 1$ and common difference $d = 1$.The formula for the sum of the first $n$ terms of an $A.P.$ is $S_n = \frac{n}{2}[2a + (n - 1)d]$.Substituting the values $a = 1$ and $d = 1$ into the formula:$S_n = \frac{n}{2}[2(1) + (n - 1)(1)]$$S_n = \frac{n}{2}[2 + n - 1]$$S_n = \frac{n(n + 1)}{2}$.

The sum of the first $n$ natural numbers is:

Similar Questions

$11^2 + 12^2 + 13^2 + \dots + 20^2 = $

If the third term of a $G.P.$ is $4$,then the product of its first $5$ terms is:

$A$ body falls $16\, m$ in the first second of its motion,$48\, m$ in the second,$80\, m$ in the third,$112\, m$ in the fourth and so on. How far does it fall during the $11^{th}$ second of its motion? (in $m$)

The $9^{th}$ term of the series $27 + 9 + 5\frac{2}{5} + 3\frac{6}{7} + \dots$ will be

The sum of the first $20$ terms of the series $1 + \frac{3}{2} + \frac{7}{4} + \frac{15}{8} + \frac{31}{16} + \dots$ is?

Vedclass Test Series

Exam Paper Generator

Online Exam Module