The sum to $n$ terms of the series $2^2 + 4^2 + 6^2 + \dots$ is
- A$\frac{n(n + 1)(2n + 1)}{3}$
- B$\frac{2n(n + 1)(2n + 1)}{3}$
- C$\frac{n(n + 1)(2n + 1)}{6}$
- D$\frac{n(n + 1)(2n + 1)}{9}$
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