The total number of two-digit positive multip | vedclass

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Question

(A) The two-digit positive multiples of $7$ form an Arithmetic Progression $(A.P.)$ starting from $14$ and ending at $98$.The sequence is: $14, 21, 28

Vedclass · Accepted Answer

$13$

Vedclass · Answer

(A) The two-digit positive multiples of $7$ form an Arithmetic Progression $(A.P.)$ starting from $14$ and ending at $98$.The sequence is: $14, 21, 28, \dots, 98$.Here,the first term $a = 14$,the common difference $d = 7$,and the last term $T_n = 98$.Using the formula for the $n^{th}$ term of an $A.P.$: $T_n = a + (n - 1)d$.Substituting the values: $98 = 14 + (n - 1)7$.Subtracting $14$ from both sides: $84 = (n - 1)7$.Dividing by $7$: $12 = n - 1$.Therefore,$n = 13$.Thus,there are $13$ two-digit positive multiples of $7$.

The total number of two-digit positive multiples of $7$ is:

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