The two circles $x^2 + y^2 - 2x + 6y + 6 = 0$ and $x^2 + y^2 - 5x + 6y + 15 = 0$ touch each other. The equation of their common tangent is
- A$x = 3$
- B$y = 6$
- C$7x - 12y - 21 = 0$
- D$7x + 12y + 21 = 0$
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View SolutionThe combined equation of the direct common tangents of the circles $x^2+y^2-2x-2y-2=0$ and $x^2+y^2+4x+6y+12=0$ is:
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