The velocity of light emitted by a source $S$ observed by an observer $O$,who is at rest with respect to $S$,is $c$. If the observer moves towards $S$ with velocity $v$,the velocity of light as observed will be
- A$c + v$
- B$c - v$
- C$c$
- D$\sqrt{1 - \frac{v^2}{c^2}}$
Explore More
Similar Questions
The $6563 \ \mathring{A}$ line emitted by a hydrogen atom in a star is found to be red-shifted by $5 \ \mathring{A}$. The speed with which the star is receding from the Earth is:
Medium
View SolutionIf a source of light is moving away from a stationary observer,then the frequency of light wave appears to change because of
Easy
View SolutionThe wavelength of light coming from a star is observed to increase by $0.4\%$. What is the velocity of the star?
Easy
View SolutionIf a star emitting yellow light is accelerated towards the Earth,then to an observer on Earth,it will appear:
$A$ star emitting light of wavelength $5896 \ \mathring{A}$ is moving away from the earth with a speed of $3600 \ km/s$. The wavelength of light observed on earth will be:
($c = 3 \times 10^8 \ m/s$ is the speed of light)
($c = 3 \times 10^8 \ m/s$ is the speed of light)
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo