The volume of a metal sphere increases by 0.3 | vedclass

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(C) The fractional change in volume is given by $\frac{\Delta V}{V} = \gamma \Delta T$,where $\gamma$ is the coefficient of volume expansion.Given $\f

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$2 	imes 10^{-5} /^{\circ} C$

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(C) The fractional change in volume is given by $\frac{\Delta V}{V} = \gamma \Delta T$,where $\gamma$ is the coefficient of volume expansion.Given $\frac{\Delta V}{V} = 0.30 \% = 0.003$ and $\Delta T = 50^{\circ} C$.Substituting these values: $0.003 = \gamma (50^{\circ} C) \Rightarrow \gamma = \frac{0.003}{50} = 6 	imes 10^{-5} /^{\circ} C$.We know that the coefficient of volume expansion $\gamma$ is related to the coefficient of linear expansion $\alpha$ by $\gamma = 3\alpha$.Therefore,$\alpha = \frac{\gamma}{3} = \frac{6 	imes 10^{-5}}{3} = 2 	imes 10^{-5} /^{\circ} C$.

The volume of a metal sphere increases by $0.30 \%$,when its temperature is raised by $50^{\circ} C$. The coefficient of linear expansion of the metal is

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