The work done in an adiabatic change in an ideal gas depends upon only

The figure shows an adiabatic curve on a $\log T$ and $\log V$ scale for an ideal gas. The gas is ............

Pressure-temperature relationship for an ideal gas undergoing adiabatic change is $\left( \gamma = C_p/C_v \right)$

$A$ motor tube is filled with air at $27^{\circ}C$ and a pressure of $8 \text{ atm}$. If the tube suddenly bursts,what will be the final temperature of the air? $(\gamma = 1.5)$

$A$ monoatomic ideal gas is compressed adiabatically to $\left(\frac{1}{27}\right)$ of its initial volume. If the initial temperature of the gas is $T \ K$ and the final temperature is $xT \ K$, the value of $x$ is:

$A$ monatomic gas at a pressure of $100 \text{ kPa}$ expands adiabatically such that its final volume becomes $8$ times its initial volume. If the work done during the process is $180 \text{ J}$, then the initial volume of the gas is (in $\text{ cm}^3$)