The zeros of p(x) = x^{3} - 4x are .......... | vedclass

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(D) To find the zeros of the polynomial $p(x) = x^{3} - 4x$,we set $p(x) = 0$.$x^{3} - 4x = 0$Factor out $x$ from the expression:$x(x^{2} - 4) = 0$Usi

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$0, \pm 2$

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(D) To find the zeros of the polynomial $p(x) = x^{3} - 4x$,we set $p(x) = 0$.$x^{3} - 4x = 0$Factor out $x$ from the expression:$x(x^{2} - 4) = 0$Using the difference of squares formula $a^{2} - b^{2} = (a - b)(a + b)$,we can write $x^{2} - 4$ as $(x - 2)(x + 2)$:$x(x - 2)(x + 2) = 0$Setting each factor to zero,we get:$x = 0$,$x - 2 = 0 \Rightarrow x = 2$,and $x + 2 = 0 \Rightarrow x = -2$.Thus,the zeros are $0, 2, -2$,which can be written as $0, \pm 2$.

The zeros of $p(x) = x^{3} - 4x$ are .............

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