There are 60 terms in a finite A.P.. Its firs | vedclass

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(D) Given: Number of terms $n = 60$,first term $a = 7$,and last term $a_{60} = 125$.Using the formula for the $n^{th}$ term of an $A.P.$,$a_n = a + (n

Vedclass · Accepted Answer

$69$

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(D) Given: Number of terms $n = 60$,first term $a = 7$,and last term $a_{60} = 125$.Using the formula for the $n^{th}$ term of an $A.P.$,$a_n = a + (n - 1)d$.For the $60^{th}$ term: $125 = 7 + (60 - 1)d$.$125 - 7 = 59d$.$118 = 59d$.$d = 118 / 59 = 2$.Now,find the $32^{nd}$ term $(a_{32})$:$a_{32} = a + (32 - 1)d$.$a_{32} = 7 + 31(2)$.$a_{32} = 7 + 62 = 69$.Therefore,the $32^{nd}$ term is $69$.

There are $60$ terms in a finite $A.P.$. Its first term is $7$ and the last term is $125$. Find its $32^{nd}$ term.

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