Three amplifiers with voltage gains 10, 20 an | vedclass

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(A) Given, voltage gains of three amplifiers are $A_1 = 10, A_2 = 20$, and $A_3 = 30$.The peak value of the input signal is $V_i = 1 mV = 10^{-3} \,V$

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) Given, voltage gains of three amplifiers are $A_1 = 10, A_2 = 20$, and $A_3 = 30$.The peak value of the input signal is $V_i = 1 mV = 10^{-3} \,V$.When amplifiers are connected in series, the total voltage gain $A$ is the product of individual gains:$A = A_1 	imes A_2 	imes A_3 = 10 	imes 20 	imes 30 = 6000$.The relationship between output voltage $V_0$ and input voltage $V_i$ is given by $A = \frac{V_0}{V_i}$.Therefore, the peak output voltage is $V_0 = A 	imes V_i = 6000 	imes 10^{-3} \,V = 6 \,V$.

Three amplifiers with voltage gains $10, 20$ and $30$ are connected in series. If the input signal has a peak value of $1 mV$, then the peak value of the output voltage is (in $\,V$)

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