Three blocks of masses 2 , kg, 3 , kg and 5 , | vedclass

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(C) First,calculate the acceleration $a$ of the entire system.The total mass $M = m_1 + m_2 + m_3 = 2 \, kg + 3 \, kg + 5 \, kg = 10 \, kg$.The total

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$8$

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(C) First,calculate the acceleration $a$ of the entire system.The total mass $M = m_1 + m_2 + m_3 = 2 \, kg + 3 \, kg + 5 \, kg = 10 \, kg$.The total force applied is $F = 10 \, N$.Using Newton's second law,$F = Ma$,we get $10 = 10 	imes a$,so $a = 1 \, m/s^2$.Now,consider the system of the two blocks behind the $2 \, kg$ block (i.e.,the $3 \, kg$ and $5 \, kg$ blocks) to find the tension $T_1$.The tension $T_1$ is responsible for pulling the combined mass of the $3 \, kg$ and $5 \, kg$ blocks.$T_1 = (m_2 + m_3) 	imes a = (3 \, kg + 5 \, kg) 	imes 1 \, m/s^2 = 8 \, N$.

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