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(D) The circuit consists of two inductors,each of inductance $L/2$,connected in parallel,which are then connected in series with an inductor of induct

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$L$

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(D) The circuit consists of two inductors,each of inductance $L/2$,connected in parallel,which are then connected in series with an inductor of inductance $3L/4$.First,calculate the equivalent inductance $L_p$ of the two inductors in parallel:$\frac{1}{L_p} = \frac{1}{L/2} + \frac{1}{L/2} = \frac{2}{L} + \frac{2}{L} = \frac{4}{L}$$	herefore L_p = \frac{L}{4}$Now,calculate the total equivalent inductance $L_{eq}$ by adding the series inductor:$L_{eq} = L_p + \frac{3L}{4} = \frac{L}{4} + \frac{3L}{4} = \frac{4L}{4} = L$

Three inductances are connected as shown in the figure. The equivalent inductance is

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