Three pieces of timber 42 m,49 m,and 63 m | vedclass

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(A) To find the greatest possible length of each plank,we need to calculate the Highest Common Factor $(HCF)$ of the lengths of the timber pieces,whic

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(A) To find the greatest possible length of each plank,we need to calculate the Highest Common Factor $(HCF)$ of the lengths of the timber pieces,which are $42 \ m$,$49 \ m$,and $63 \ m$.Step $1$: Find the prime factorization of each number:$42 = 2 	imes 3 	imes 7$$49 = 7 	imes 7$$63 = 3 	imes 3 	imes 7$Step $2$: Identify the common factor$(s)$ present in all three numbers:The only common factor is $7$.Therefore,the $HCF$ of $42, 49,$ and $63$ is $7$.The greatest possible length of each plank is $7 \ m$.

Three pieces of timber $42 \ m$,$49 \ m$,and $63 \ m$ long have to be divided into planks of the same length. What is the greatest possible length of each plank (in $m$)?

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