To estimate g from g=4 pi^2 frac{L}{T^2},the | vedclass

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(A) Given the formula for acceleration due to gravity: $g = 4 \pi^2 \frac{L}{T^2}$.To find the relative error in $g$,we use the propagation of error f

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$\pm 8 \%$

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(A) Given the formula for acceleration due to gravity: $g = 4 \pi^2 \frac{L}{T^2}$.To find the relative error in $g$,we use the propagation of error formula:$\frac{\Delta g}{g} = \frac{\Delta L}{L} + 2 \frac{\Delta T}{T}$.Given that the percentage error in $L$ is $\frac{\Delta L}{L} 	imes 100 = \pm 2 \%$ and the percentage error in $T$ is $\frac{\Delta T}{T} 	imes 100 = \pm 3 \%$.Substituting these values into the error equation:$\frac{\Delta g}{g} 	imes 100 = \left( \frac{\Delta L}{L} 	imes 100 ight) + 2 \left( \frac{\Delta T}{T} 	imes 100 ight)$.$\frac{\Delta g}{g} 	imes 100 = \pm 2 \% + 2 	imes (\pm 3 \%) = \pm 2 \% + \pm 6 \% = \pm 8 \%$.Therefore,the error in the estimated $g$ is $\pm 8 \%$.

To estimate $g$ from $g=4 \pi^2 \frac{L}{T^2}$,the error in the measurement of $L$ is $\pm 2 \%$ and the error in the measurement of $T$ is $\pm 3 \%$. The error in the estimated $g$ will be

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