Two resistances $60 \pm 0.36 \ \Omega$ and $30 \pm 0.09 \ \Omega$ are connected in parallel. The equivalent resistance is

$A$ physical parameter $a$ can be determined by measuring the parameters $b, c, d$ and $e$ using the relation $a = \frac{b^\alpha c^\beta}{d^\gamma e^\delta}$. If the maximum percentage errors in the measurement of $b, c, d$ and $e$ are $b_1\%, c_1\%, d_1\%$ and $e_1\%$ respectively,then the maximum percentage error in the value of $a$ determined by the experiment is:

$Assertion$ : When percentage errors in the measurement of mass and velocity are $1\%$ and $2\%$ respectively,the percentage error in $K.E.$ is $5\%$.
$Reason$ : $\frac{{\Delta E}}{E} = \frac{{\Delta m}}{m} + \frac{{2\Delta v}}{v}$

Two resistors of resistances $R_1 = (300 \pm 3) \,\Omega$ and $R_2 = (500 \pm 4) \,\Omega$ are connected in series. The equivalent resistance of the series combination is

$A$ cuboid has volume $V = l \times l \times \sqrt{l} = l^{2.5}$, where $l$ is the length of one side. When the length $l$ is measured by a meter scale of least count $1 \text{ mm}$, the relative percentage error in the measurement of its volume is $6.25\%$. Then the relative percentage error in measurement of its length and the value of the length $l$ is:

If the error in measuring the diameter of a circle is $4\%$,the error in the radius of the circle would be (in $\%$)