Two adjacent sides of a rectangle measure 12 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a rectangle,each angle is a right angle $(90^{\circ})$. Let the sides of the rectangle be $a = 12$ and $b = 35$. The diagonal $d$ of the rectan

Vedclass · Accepted Answer

$37$

Vedclass · Answer

(A) In a rectangle,each angle is a right angle $(90^{\circ})$. Let the sides of the rectangle be $a = 12$ and $b = 35$. The diagonal $d$ of the rectangle forms a right-angled triangle with the two adjacent sides. According to the Pythagorean theorem,$d^2 = a^2 + b^2$. Substituting the given values: $d^2 = 12^2 + 35^2$. $d^2 = 144 + 1225$. $d^2 = 1369$. Taking the square root of both sides: $d = \sqrt{1369} = 37$. Therefore,the length of the diagonal is $37$.

Two adjacent sides of a rectangle measure $12$ and $35$. Then,the length of a diagonal of the rectangle is..........

Similar Questions

In $\Delta PQR$,$m\angle P = 90^{\circ}$ and $\overline{PM}$ is an altitude. If $PQ = \sqrt{20}$ and $QM = 4$,then $RM = \ldots \ldots .$

The perimeter of equilateral $\Delta ABC$ is $30$. Find its area. (in $\sqrt{3}$)

In $\Delta ABC$,$A-P-B$,$A-Q-C$ and $\overline{PQ} \parallel \overline{BC}$. If $AP = 2$,$AB = 6$ and $AC = 9$,find $AQ$.

In $\Delta ABC$,$m\angle B = 90^{\circ}$ and $\overline{BM}$ is a median. If $AB = 15$ and $BM = 12.5$,find $BC$.

$O$ is the point of intersection of the diagonals $AC$ and $BD$ of a trapezium $ABCD$ with $AB \parallel DC$. Through $O$,a line segment $PQ$ is drawn parallel to $AB$ meeting $AD$ in $P$ and $BC$ in $Q$. Prove that $PO = QO$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module