Two bodies having same mass 40, kg are moving | vedclass

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(D) According to the law of conservation of linear momentum,the total momentum before collision is equal to the total momentum after collision.Let the

Vedclass · Accepted Answer

$1.5$

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(D) According to the law of conservation of linear momentum,the total momentum before collision is equal to the total momentum after collision.Let the mass of each body be $m = 40\, kg$.Let the velocity of the first body be $v_1 = 10\, m/s$ and the velocity of the second body be $v_2 = -7\, m/s$ (since they move in opposite directions).Let the final velocity of the combined mass be $v$.Using the formula: $m_1v_1 + m_2v_2 = (m_1 + m_2)v$Substituting the values: $(40 	imes 10) + (40 	imes -7) = (40 + 40)v$$400 - 280 = 80v$$120 = 80v$$v = 120 / 80 = 1.5\, m/s$.Therefore,the velocity of the combination is $1.5\, m/s$.

Two bodies having same mass $40\, kg$ are moving in opposite directions,one with a velocity of $10\, m/s$ and the other with $7\, m/s$. If they collide and move as one body,the velocity of the combination is ........ $m/s$.

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