Two identical long current-carrying wires are bent into the shapes shown in the figures. If the magnitudes of the magnetic fields at the centers $P$ and $Q$ of the quarter-circular arcs are $B_1$ and $B_2$ respectively, then the ratio $\frac{B_1}{B_2}$ is:

  • A
    $\frac{2+\pi}{2-\pi}$
  • B
    $\frac{2+\pi}{\pi-2}$
  • C
    $\frac{2+\pi}{2}$
  • D
    $\frac{2+\pi}{\pi}$

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