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(B) The magnetic moment is a vector quantity. When two magnets of equal magnetic moment $M$ are placed at right angles to each other,their resultant m

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$\sqrt{2} \,M$

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(B) The magnetic moment is a vector quantity. When two magnets of equal magnetic moment $M$ are placed at right angles to each other,their resultant magnetic moment $M_{net}$ is given by the vector sum of the individual magnetic moments.Since the angle between the two magnetic moments is $90^{\circ}$,the magnitude of the resultant magnetic moment is calculated as:$M_{net} = \sqrt{M^2 + M^2 + 2MM \cos(90^{\circ})}$Since $\cos(90^{\circ}) = 0$,this simplifies to:$M_{net} = \sqrt{M^2 + M^2} = \sqrt{2M^2} = \sqrt{2} \,M$

Two magnets,each of magnetic moment $M$,are placed so as to form a cross at right angles to each other. The magnetic moment of the system will be

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