Two masses of 1,kg and 16,kg are moving with | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by the formula $P = \sqrt{2mE}$.Since the kinetic energy $E$

Vedclass · Accepted Answer

$1:4$

Vedclass · Answer

(B) The relationship between linear momentum $P$,mass $m$,and kinetic energy $E$ is given by the formula $P = \sqrt{2mE}$.Since the kinetic energy $E$ is equal for both masses,we have $P \propto \sqrt{m}$.Therefore,the ratio of the linear momenta is $\frac{P_1}{P_2} = \sqrt{\frac{m_1}{m_2}}$.Given $m_1 = 1\,kg$ and $m_2 = 16\,kg$,we get $\frac{P_1}{P_2} = \sqrt{\frac{1}{16}} = \frac{1}{4}$.Thus,the ratio is $1:4$.

Two masses of $1\,kg$ and $16\,kg$ are moving with equal kinetic energy. The ratio of the magnitude of their linear momentum is:

Similar Questions

If the kinetic energy of a body is increased by $300\%$,then the percentage change in momentum will be:

Two bodies of masses $m$ and $2m$ have the same momentum. Their respective kinetic energies $E_1$ and $E_2$ are in the ratio:

$A$ light body and a heavy body have the same kinetic energy. Which one has a greater momentum?

The work done by a force on a body of mass $5 \,kg$ to accelerate it in the direction of the force from rest to $20 \,m/s$ in $10 \,s$ is:

Two bodies of masses $1 \ g$ and $4 \ g$ are moving with the same kinetic energy. What is the ratio of their linear momenta?

Vedclass Test Series

Exam Paper Generator

Online Exam Module