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(B) Let the width of each plate be $b$. Due to surface tension, the liquid will rise to a height $h$.The upward force due to surface tension acts alon

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$\frac{2T \cos 	heta}{xdg}$

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(B) Let the width of each plate be $b$. Due to surface tension, the liquid will rise to a height $h$.The upward force due to surface tension acts along the two contact lines of length $b$ each:$F_{	ext{up}} = 2 	imes (T \cos 	heta 	imes b) = 2Tb \cos 	heta$ ... $(i)$The weight of the liquid column raised between the plates is given by:$W = 	ext{Volume} 	imes 	ext{density} 	imes g = (b 	imes x 	imes h) 	imes d 	imes g$ ... (ii)At equilibrium, the upward force balances the weight of the liquid column:$2Tb \cos 	heta = bxhdg$Dividing both sides by $b$, we get:$2T \cos 	heta = xhdg$Therefore, the height of the liquid rise is:$h = \frac{2T \cos 	heta}{xdg}$

Two parallel glass plates are dipped partly in a liquid of density $d$ while keeping them vertical. If the distance between the plates is $x$, the surface tension of the liquid is $T$, and the angle of contact is $\theta$, then the rise of the liquid between the plates due to capillarity will be:

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