Two refracting media are separated by a spher | vedclass

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(D) The refraction formula for a spherical surface is given by: $\frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R}$.In the given figure, the

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Both $(A)$ and $(C)$

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(D) The refraction formula for a spherical surface is given by: $\frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R}$.In the given figure, the center of curvature $C$ lies to the left of the pole, so $R$ is negative (let $R = -|R|$).Thus, $\frac{\mu_2}{v} = \frac{\mu_1}{u} + \frac{\mu_2 - \mu_1}{-|R|}$.Case $(A)$: If $\mu_2 > \mu_1$, then $\mu_2 - \mu_1 > 0$. For a real object, $u Case $(C)$: If $\mu_1 > \mu_2$, then $\mu_2 - \mu_1  0$. Then $\frac{\mu_2}{v} = \frac{\mu_1}{u} + \frac{k}{|R|}$. For a virtual object, $u > 0$. Here, both terms on the right are positive, so $v$ must be positive, meaning only a real image is formed. Thus, a virtual image cannot be formed.Therefore, both $(A)$ and $(C)$ are correct.

Two refracting media are separated by a spherical interface as shown in the figure. $PP'$ is the principal axis, $\mu_1$ and $\mu_2$ are the refractive indices of the medium of incidence and the medium of refraction respectively. Then:

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