Two rods $A$ and $B$ of the same cross-sectional area $A$ and length $l$ are connected in series between a source $(T_1 = 100^{\circ}C)$ and a sink $(T_2 = 0^{\circ}C)$ as shown in the figure. The rods are laterally insulated. If the thermal conductivities of rods $A$ and $B$ are $3K$ and $K$ respectively,and $T_A$ and $T_B$ are the temperature drops across rods $A$ and $B$,then:

  • A
    $\frac{T_A}{T_B} = \frac{3}{1}$
  • B
    $\frac{T_A}{T_B} = \frac{1}{3}$
  • C
    $\frac{T_A}{T_B} = \frac{3}{4}$
  • D
    $\frac{T_A}{T_B} = \frac{4}{3}$

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In steady state heat conduction,the equations that determine the heat current $j(r)$ [heat flowing per unit time per unit area] and temperature $T(r)$ in space are exactly the same as those governing the electric field $E(r)$ and electrostatic potential $V(r)$ with the equivalence given in the table below.
Heat flow Electrostatics
$T(r)$ $V(r)$
$j(r)$ $E(r)$

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The unit of thermal conductivity is

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