Two rods $A$ and $B$ of the same cross-sectional area $A$ and length $l$ are connected in series between a source $(T_1 = 100^{\circ}C)$ and a sink $(T_2 = 0^{\circ}C)$ as shown in the figure. The rods are laterally insulated. If $G_A$ and $G_B$ are the temperature gradients across rod $A$ (thermal conductivity $3K$) and rod $B$ (thermal conductivity $K$),then:

  • A
    $\frac{G_A}{G_B} = \frac{3}{1}$
  • B
    $\frac{G_A}{G_B} = \frac{1}{3}$
  • C
    $\frac{G_A}{G_B} = \frac{3}{4}$
  • D
    $\frac{G_A}{G_B} = \frac{4}{3}$

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