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(D) Since both spheres are made of the same metal,their density $ho$ is the same.Weight $W = 	ext{Volume} 	imes 	ext{Density} 	imes g = \frac{4}

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$5$

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(D) Since both spheres are made of the same metal,their density $ho$ is the same.Weight $W = 	ext{Volume} 	imes 	ext{Density} 	imes g = \frac{4}{3} \pi r^3 ho g$.Therefore,the ratio of the weights is equal to the ratio of the volumes: $\frac{W_1}{W_2} = \frac{r_1^3}{r_2^3}$.Given $W_1 = 5920 \, g$,$W_2 = 740 \, g$,and diameter of the smaller sphere $d_2 = 5 \, cm$,so $r_2 = 2.5 \, cm$.$\frac{5920}{740} = \frac{r_1^3}{(2.5)^3}$.$8 = \frac{r_1^3}{15.625}$.$r_1^3 = 8 	imes 15.625 = 125$.$r_1 = \sqrt[3]{125} = 5 \, cm$.

Two solid spheres made of the same metal have weights $5920 \, g$ and $740 \, g$ respectively. Determine the radius of the larger sphere,if the diameter of the smaller one is $5 \, cm$. (in $cm$)

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