Two solutions of electrolytes $X$ and $Y$ are taken in two beakers and diluted by adding $500 \ mL$ of water. The molar conductivity $(\Lambda_m)$ of $X$ increases by $1.5$ times,while that of $Y$ increases by $20$ times. What could be the electrolytes $X$ and $Y$?

  • A
    $X \to NaCl, Y \to KCl$
  • B
    $X \to NaCl, Y \to CH_3COOH$
  • C
    $X \to KOH, Y \to NaOH$
  • D
    $X \to CH_3COOH, Y \to NaCl$

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Similar Questions

Calculate the cell constant of a conductivity cell containing $0.01 \ M \ AgNO_3$ solution having a resistance of $1440 \ \Omega$ and a conductivity of $0.001262 \ \Omega^{-1} \ cm^{-1}$. (in $cm^{-1}$)

The molar conductivity of $0.1 \ M$ $BaCl_2$ solution is $106 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ at $25^{\circ} C$. What is its conductivity?

Define $\Lambda _m = \frac{\kappa \times 1000}{C}$ where $C$ is concentration in $mol \ L^{-1}$ and $\kappa$ is conductivity in $S \ cm^{-1}$.

How is the cell constant determined?

The specific conductance $(k)$ of $0.02 \ M$ aqueous acetic acid solution at $298 \ K$ is $1.65 \times 10^{-4} \ S \ cm^{-1}$. The degree of dissociation $(\alpha)$ of acetic acid is: [Given: $\lambda_{H^{+}}^{\infty} = 349.1 \ S \ cm^2 \ mol^{-1}$ and $\lambda_{CH_3COO^{-}}^{\infty} = 40.9 \ S \ cm^2 \ mol^{-1}$]

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