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Question

(A) According to the shell theorem,the electric field inside a uniformly charged spherical shell is zero. Therefore,the electric force on the charge $

Vedclass · Accepted Answer

$\frac{qQ}{361\pi \varepsilon_0 d^2}$ to the left

Vedclass · Answer

(A) According to the shell theorem,the electric field inside a uniformly charged spherical shell is zero. Therefore,the electric force on the charge $q$ due to the shell in which it is placed (let's call it shell $A$) is zero.The electric force on the charge $q$ is only due to the other shell (shell $B$). The distance between the center of shell $B$ and the charge $q$ is $10d + d/2 = 19d/2$.Since shell $B$ acts as a point charge $Q$ at its center for external points,the force is given by Coulomb's Law:$F = \frac{1}{4\pi \varepsilon_0} \frac{Qq}{(19d/2)^2} = \frac{Qq}{4\pi \varepsilon_0 (361d^2/4)} = \frac{Qq}{361\pi \varepsilon_0 d^2}$.Since both charges are positive,the force is repulsive,meaning it acts away from shell $B$,which is towards the left.

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