Value of the objective function $Z = -50x + 20y$ subject to the constraints $2x - y \geq -5$,$3x + y \geq 3$,$2x - 3y \leq 12$,$x \geq 0$,$y \geq 0$. The corner points of the feasible region are $(0, 5)$,$(0, 3)$,$(1, 0)$,and $(6, 0)$. At which point is the value of $Z$ minimum?
- A$(0, 3)$
- B$(6, 0)$
- C$(0, 5)$
- D$(1, 0)$
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The corner points of the feasible region determined by the system of linear constraints are $(2, 72)$,$(15, 20)$,and $(40, 15)$. Let $Z = 6x + 3y$ be the objective function. The minimum value of $Z$ occurs at:
The corner points of the feasible region determined by the system of linear constraints are $(0,0), (0,40), (20,40), (60,20), (60,0)$. The objective function is $z=4x+3y$. Compare the quantity in Column $A$ and Column $B$.
Column Value $A$. Maximum of $z$ $300$ $B$. Constant value $325$
| Column | Value |
| $A$. Maximum of $z$ | $300$ |
| $B$. Constant value | $325$ |
Medium
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The feasible region for a $LPP$ is shown in the figure. Find the maximum value of $Z=11x+7y$.
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