What force should be applied on the wedge so | vedclass

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(B) For the block of mass $m$ to remain stationary with respect to the wedge of mass $M$,the pseudo force acting on the block must balance the compone

Vedclass · Accepted Answer

$F=(M+m) g 	an 	heta$

Vedclass · Answer

(B) For the block of mass $m$ to remain stationary with respect to the wedge of mass $M$,the pseudo force acting on the block must balance the component of gravity along the incline.$1$. Let the acceleration of the system be $a$. The total mass of the system is $(M+m)$. The force applied is $F = (M+m)a$,so $a = \frac{F}{M+m} \dots (1)$.$2$. In the frame of the wedge,the block experiences a pseudo force $ma$ acting horizontally to the left. The components of forces acting on the block parallel to the inclined surface are:- The component of pseudo force: $ma \cos 	heta$- The component of gravity: $mg \sin 	heta$$3$. For the block to be at rest on the wedge,these forces must be equal:$ma \cos 	heta = mg \sin 	heta$$a \cos 	heta = g \sin 	heta$$a = g 	an 	heta$$4$. Substituting the value of $a$ into equation $(1)$:$F = (M+m) g 	an 	heta$.

What force should be applied on the wedge so that the block over it does not move? (All surfaces are smooth)

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