What is the conductivity of $0.02 \ M \ KCl$ solution if the cell constant is $1.29 \ cm^{-1}$ and the resistance is $645 \ \Omega$?

At $25^o C$,the molar conductivity of a $0.1 \, N \, CH_3COOH$ solution is $80 \, S \, cm^2 \, mol^{-1}$ and the molar conductivity at infinite dilution is $400 \, S \, cm^2 \, mol^{-1}$. What is the degree of dissociation $(\alpha)$ of $CH_3COOH$?

The factor which is not affecting the conductivity of any solution is

Which of the following statements is incorrect?

When a certain conductivity cell was filled with $0.1 \ M \ KCl$,it had a resistance of $85 \ \Omega$ at $25 \ ^oC$. When the same cell was filled with an aqueous solution of $0.052 \ M$ unknown electrolyte,the resistance was $96 \ \Omega$. Calculate the molar conductivity of the unknown electrolyte at this concentration ............. $\Omega^{-1} \ cm^2 \ mol^{-1}$ (Given: Specific conductance of $0.1 \ M \ KCl = 1.29 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$)

Molar conductivity of $0.04 \ M \ BaCl_2$ solution is $230 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ at $27^{\circ} C$. What is its conductivity?